#include using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=0){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} template bool inside(T l,T x,T r){return l<=x&&x using mint = atcoder::modint998244353; void solve(); // CYAN / FREDERIC int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ const int L = 20202; int N, W; cin >> N >> W; vector> dp1(L, {-ILL, 0}), dp2(L, {-ILL, 0}); dp1[0] = {0, 1}; dp2[0] = {0, 1}; auto op = [&](pair &a, pair b) -> void { if (chmax(a.first, b.first)) a.second = 0; if (a.first == b.first) a.second += b.second; }; rep(rp, 0, N){ int u, w; cin >> u >> w; for (int j = L - 1; j >= abs(w); j--){ auto tmp = dp1[j - abs(w)]; if (w >= 0){ tmp.first += u; op(dp1[j], tmp); } else{ tmp = dp2[j + w]; tmp.first += u; op(dp2[j], tmp); } } } pair ans = {-ILL, 0}; pair sum = {-ILL, 0}; for (int j = L - 1; j >= 0; j--){ int ind = W - j; ind *= -1; if (inside(0, ind, L)) op(sum, dp2[ind]); op(ans, {sum.first + dp1[j].first, sum.second * dp1[j].second}); } cout << ans.first << " " << ans.second.val() << "\n"; }