#include using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=0){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} template bool inside(T l,T x,T r){return l<=x&&x using mint = atcoder::modint998244353; void solve(); // CYAN / FREDERIC int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ int N, M; cin >> N >> M; vector E(N); rep(i, 0, N) cin >> E[i]; vector u(M), v(M); rep(i, 0, M) cin >> u[i] >> v[i]; vector A(1 << M), B(1 << M); rep(i, 0, 1 << M) rep(j, 0, M) if (i & (1 << j)){ A[i] += u[j]; B[i] += v[j]; } reverse(all(E)); vector dp(N + 1, vector(1 << M)); vector fr(N + 1, vector(1 << M)); rep(i, 0, N){ for (int j = (1 << M) - 1; j >= 0; j--){ for (int k = j; k >= 0; k--){ k &= j; if (B[k] <= E[i]){ if (chmax(dp[i + 1][j], A[k] + dp[i][j ^ k])){ fr[i + 1][j] = k; } } } } } cout << dp[N].back() << "\n"; int ind = (1 << M) - 1; for (int i = N; i > 0; i--){ int K = fr[i][ind]; ind ^= K; cout << pop_count(K); rep(j, 0, M) if (K & (1 << j)){ cout << " " << j + 1; } cout << "\n"; } }