#include using namespace std; template struct Fp { long long val; constexpr Fp(long long v = 0) noexcept : val(v % MOD) { if (val < 0) val += MOD; } constexpr int getmod() { return MOD; } constexpr Fp operator - () const noexcept { return val ? MOD - val : 0; } constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; } constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; } constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; } constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; } constexpr Fp& operator += (const Fp& r) noexcept { val += r.val; if (val >= MOD) val -= MOD; return *this; } constexpr Fp& operator -= (const Fp& r) noexcept { val -= r.val; if (val < 0) val += MOD; return *this; } constexpr Fp& operator *= (const Fp& r) noexcept { val = val * r.val % MOD; return *this; } constexpr Fp& operator /= (const Fp& r) noexcept { long long a = r.val, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } val = val * u % MOD; if (val < 0) val += MOD; return *this; } constexpr bool operator > (const Fp& r) const noexcept { return this->val > r.val; } constexpr bool operator < (const Fp& r) const noexcept { return this->val < r.val; } constexpr bool operator == (const Fp& r) const noexcept { return this->val == r.val; } constexpr bool operator != (const Fp& r) const noexcept { return this->val != r.val; } friend constexpr ostream& operator << (ostream &os, const Fp& x) noexcept { return os << x.val; } friend constexpr Fp modpow(const Fp &a, long long n) noexcept { if (n == 0) return 1; auto t = modpow(a, n / 2); t = t * t; if (n & 1) t = t * a; return t; } }; using mint = Fp<998244353>; int main(){ int x,K; cin >> x >> K; if(K > 10)return 0; mint p[2*K+1]; mint p2[2*K+1]; p[0] = 1; p2[0] = 1; for(int i = 1; i <= 2*K; i++)p[i] = p[i-1] * x; for(int i = 1; i <= 2*K; i++)p2[i] = p2[i-1] * (mint(100) - x); mint ans = 0; for(int i = 0; i < (1<<2*K); i++){ if(__builtin_popcount(i) != K)continue; int now = 0; int d = 0; bool ok = 1; for(int j = 0; j < 2*K; j++){ if(i >> j & 1)now++; else now--; d = max(d , now); if(now < 0)ok = 0; } if(ok)ans += p[K] * p2[K] * d; } ans /= modpow(mint(100) , 2*K); cout << ans << endl; return 0; }