#include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; const int inf=1<<30; const ll INF=1LL<<62; typedef pair P; typedef pair PP; const ll MOD=998244353; const int dy[]={0,1,0,-1}; const int dx[]={1,0,-1,0}; const int mod = 998244353; struct mint { long long x; // typedef long long long long; mint(long long x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;}//後ろのconstはメンバxを変更しないことを示す mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} bool operator==(const mint a) const {return a.x==x;} mint pow(unsigned long long int t) const { assert(t>=0); if (!t) return 1; //aがtで割り切れない場合には t%=(mod-1)をして良い mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; std::istream& operator>>(std::istream& is, mint& a) { return is >> a.x;} std::ostream& operator<<(std::ostream& os, const mint& a) { return os << a.x;} struct combination { std::vector fact, ifact; combination(int n):fact(n+1),ifact(n+1) { assert(n < mod); fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; return fact[n]*ifact[k]*ifact[n-k]; } }; combination comb(2*1000000+10); const int MAXN=5000+10; vector c(MAXN+1); vector> s(MAXN+1,vector(MAXN+1,0)); vector c_used(MAXN+1,false); vector> s_used(MAXN+1,vector(MAXN+1,false)); mint q; mint p; mint C(int n); mint S(int n,int k); mint C(int n){ if(c_used[n])return c[n]; c_used[n]=true; mint res=1; for(int i=1;i<=n-1;i++){ res-=S(n,i); } return c[n]=res; }; mint S(int n,int k){ if(s_used[n][k])return s[n][k]; s_used[n][k]=true; mint res=comb(n-1,k-1)*q.pow((n-k)*k)*C(k); return s[n][k]=res; }; int main(){ int N,x; cin>>N>>x; p=(mint)x/100; q=(mint)1-p; mint ans=0; for(int k=1;k<=N;k++){ ans+=(mint)k*S(N,k); } cout<