#include using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=0){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} template bool inside(T l,T x,T r){return l<=x&&x using F = array; F op(F l, F r){ rep(i, 0, 8) chmin(l[i], r[i]); return l; } F e(){ F tmp; rep(i, 0, 8) tmp[i] = ILL; return tmp; } void solve(); // CYAN / FREDERIC int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; //cin >> t; rep(i, 0, t) solve(); } void solve(){ int N; cin >> N; vector> A(N, vector(3)); atcoder::segtree seg(N); rep(i, 0, N){ ll a, b, d; cin >> a >> b >> d; A[i][0] = b - a; A[i][1] = a + b; A[i][2] = d - b; A[i][2] *= 2; F tmp; rep(j, 0, 8){ ll x = 0; rep(k, 0, 3) if (j & (1 << k)) x += A[i][k]; tmp[j] = x; } seg.set(i, tmp); } int Q; cin >> Q; rep(i, 0, Q){ int s, l, r; cin >> s >> l >> r; s--, l--; auto tmp = seg.prod(l, r); bool ok = 1; rep(j, 0, 8){ rep(k, 0, 3) if ((j & (1 << k)) == 0) tmp[j] += A[s][k]; if (tmp[j] <= 0) ok = 0; //cout << tmp[j] << "\n"; } yneos(ok); } }