#pragma GCC target("avx") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include using namespace std; #define rep(i,n) for(int i = 0; i < (int)n; i++) #define FOR(n) for(int i = 0; i < (int)n; i++) #define repi(i,a,b) for(int i = (int)a; i < (int)b; i++) #define all(x) x.begin(),x.end() //#define mp make_pair #define vi vector #define vvi vector #define vvvi vector #define vvvvi vector #define pii pair #define vpii vector> template bool chmax(T &a, const T b) {if(a bool chmin(T &a, const T b) {if(a>b) {a=b; return true;} else {return false;}} using ll = long long; using ld = long double; using ull = unsigned long long; const ll INF = numeric_limits::max() / 2; const ld pi = 3.1415926535897932384626433832795028; const ll mod = 998244353; int dx[] = {1, 0, -1, 0, -1, -1, 1, 1}; int dy[] = {0, 1, 0, -1, -1, 1, -1, 1}; #define int long long void solve() { int n; cin >> n; vi a(n), b(n), c(n); FOR(n) cin >> a[i]; FOR(n) cin >> b[i]; FOR(n) cin >> c[i]; // i番目まででj回焼き始めてて今やいてる最中のやつがk個数 vvvi dp(n+1, vvi(3, vi(3, 0))); rep(i, n) rep(j, 3) rep(k, j+1) rep(nk, 3 + k - j) { chmax(dp[i+1][j + max(0LL, nk - k)][nk], dp[i][j][k] + (nk == 0? a[i] : nk == 1? b[i] : c[i])); } int ans = 0; rep(i, 3) rep(j, 3) chmax(ans, dp[n][i][j]); cout << ans << endl; } signed main() { cin.tie(nullptr); ios::sync_with_stdio(false); solve(); return 0; }