#include <bits/stdc++.h>
using namespace std;
#include <atcoder/modint>
using mint = atcoder::modint998244353;

#define rep(i, l, r) for (int i = (int)(l); i<(int)(r); i++)
#define ll long long

//vector<T>であらわされるn進数を10進数に変換する
template<class T>
T change_base_to_ten(const vector<T>& A, T n) {
    T ret = 0;
    T mul = 1;
    for (int i = (int)A.size()-1; i >= 0; i--) {
        ret += mul * A[i];
        mul *= n;
    }
    return ret;
}

//10進数でxのものをn進数に変換する
template<class T>
vector<T> change_base_from_ten(T x, T n, int siz) {
    vector<T> ret;
    while(x != 0) {
        ret.push_back(x%n);
        x /= n;
    }
    while((int)ret.size() < siz) ret.push_back(0);
    reverse(ret.begin(), ret.end());
    return ret;
}

//n進法の桁のvectorであるSをm進法に変換する
template<class T>
vector<T> change_base(const vector<T>& S, T n, T m) {
    T ten = change_base_to_ten(S, n);
    return change_base_from_ten(ten, m);
} 

int pow(int x, int k) {
    int ret = 1;
    rep(_, 0, k) ret *= x;
    return ret;
}

int main() {
    int N, M, K; cin >> N >> M >> K;
    vector<vector<int>> G(N);
    rep(i, 0, M) {
        int u, v; cin >> u >> v;
        u--; v--;
        G[u].push_back(v);
        G[v].push_back(u);
    }
    vector<vector<mint>> dp(pow(K+1, N), vector<mint>(N));
    rep(i, 0, N) {
        vector<int> T(N, 0);
        T[i]++;
        // cout << change_base_to_ten(T, K+1) << endl;
        dp[change_base_to_ten(T, K+1)][i] = 1;
    }
    rep(S, 0, pow(K+1, N)) {
        // cout << "S = " << S << endl;
        vector<int> T = change_base_from_ten(S, K+1, N);
        // cout << "T = " << endl;
        // for (auto v : T) cout << v << " ";
        // cout << endl;
        rep(i, 0, N) {
            // cout << "i = " << i << endl;
            for (int to : G[i]) {
                // cout << "to = " << to << endl;
                if (T[to] >= K) continue;
                auto nT = T;
                nT[to]++;
                dp[change_base_to_ten(nT, K+1)][to] += dp[S][i];
            }
        }
    }
    mint ans = 0;
    rep(i, 0, N) ans += dp.back()[i];
    cout << ans.val() << endl;
}