#include //#include using namespace std; //using namespace atcoder; using ll = long long; const ll mod = 1000000007; //const ll mod = 998244353; int dx[4] = { 0,1,0,-1 }, dy[4] = { -1,0,1,0 }; ll n, s, b, h[200009]; int main() { cin >> n >> s >> b; for (int i = 1; i <= n; i++)cin >> h[i]; ll now = s; for (int i = 1; i <= n-1; i++) { if (h[i + 1] <= h[i])now = s; else { ll dif = h[i + 1] - h[i]; ll need = (dif + b - 1LL) / b; now -= need; if (now < 0) { cout << "No" << endl; return 0; } else now = s; } } cout << "Yes" << endl; }