/**
	author:  shobonvip
	created: 2024.10.25 22:20:13
**/

#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
using namespace std;

//* ATCODER
#include<atcoder/all>
using namespace atcoder;
typedef modint998244353 mint;
//*/

/* BOOST MULTIPRECISION
#include<boost/multiprecision/cpp_int.hpp>
using namespace boost::multiprecision;
//*/

typedef long long ll;

#define rep(i, s, n) for (int i = (int)(s); i < (int)(n); i++)
#define rrep(i, s, n) for (int i = (int)(n)-1; i >= (int)(s); i--)

template <typename T> bool chmin(T &a, const T &b) {
	if (a <= b) return false;
	a = b;
	return true;
}

template <typename T> bool chmax(T &a, const T &b) {
	if (a >= b) return false;
	a = b;
	return true;
}

template <typename T> T max(vector<T> &a){
	assert(!a.empty());
	T ret = a[0];
	for (int i=0; i<(int)a.size(); i++) chmax(ret, a[i]);
	return ret;
}

template <typename T> T min(vector<T> &a){
	assert(!a.empty());
	T ret = a[0];
	for (int i=0; i<(int)a.size(); i++) chmin(ret, a[i]);
	return ret;
}

template <typename T> T sum(vector<T> &a){
	T ret = 0;
	for (int i=0; i<(int)a.size(); i++) ret += a[i];
	return ret;
}

int main(){
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	
	int n, m; cin >> n >> m;
	vector<int> d(n);
	rep(i,0,n){
		cin >> d[i];
	}

	mint alls = 1;
	rep(i,0,n){
		alls *= mint(m / d[i]);
	}

	vector<mint> e(m+1);
	rep(i,1,m+1){
		e[i] = mint(m / i).inv();
	}

	mint ans = 0;
	int mx = min(m, 200);

	rep(num,1,mx+1) {
		vector<mint> cnt(m+1);
		rep(i,1,m+1){
			cnt[i] = cnt[i-1] + (i%num==0);
		}
		vector<mint> riba(m+1);
		rep(i,1,m+1){
			for (int j=i; j<=m; j+=i){
				riba[i] += cnt[m] - cnt[j];
			}
		}

		mint tmp = 0;

		rep(i,0,n){
			if(d[i] <= mx) {
				ans += tmp * e[d[i]] * riba[d[i]];
			}else{
				ans += tmp * e[d[i]] * riba[d[i]];
			}
			if(d[i] == num) {
				tmp += e[num] * alls;
			}
		}
	}

	vector bucket(m+1, vector<int>(0));
	rep(i,0,n){
		if(d[i] > mx){
			for (int j=d[i]; j<=m; j+=d[i]){
				bucket[j].push_back(i);
			}
		}
	}

	fenwick_tree<mint> fw(n);
	rep(i,1,m+1){
		for (int j: bucket[i]){
			ans += fw.sum(j+1, n) * e[d[j]] * alls;
			fw.add(j, e[d[j]]);
		}
	}

	cout << ans.val() << '\n';
}