#include using namespace std; typedef long long ll; typedef pair pll; typedef pair pii; typedef pair pdd; typedef vector vi; typedef vector vll; typedef vector vd; typedef vector vs; typedef vector vvi; typedef vector vvvi; typedef vector vvll; typedef vector vvvll; typedef vector vpii; typedef vector vvpii; typedef vector vpll; typedef vector vvpll; typedef vector vpdd; typedef vector vvd; #define yn(ans) printf("%s\n", (ans)?"Yes":"No"); #define YN(ans) printf("%s\n", (ans)?"YES":"NO"); template bool chmax(T &a, T b) { if (a >= b) return false; a = b; return true; } template bool chmin(T &a, T b) { if (a <= b) return false; a = b; return true; } #define FOR(i, s, e, t) for ((i) = (s); (i) < (e); (i) += (t)) #define REP(i, e) for (int i = 0; i < (e); ++i) #define REP1(i, s, e) for (int i = (s); i < (e); ++i) #define RREP(i, e) for (int i = (e); i >= 0; --i) #define RREP1(i, e, s) for (int i = (e); i >= (s); --i) #define all(v) v.begin(), v.end() #define pb push_back #define qb pop_back #define pf push_front #define qf pop_front #define maxe max_element #define mine min_element ll inf = 1e18; #define DEBUG printf("%d\n", __LINE__); fflush(stdout); template void print(vector &v, bool withSize = false) { if (withSize) cout << v.size() << endl; REP(i, v.size()) cout << v[i] << " "; cout << endl; } mt19937_64 rng((unsigned int) chrono::steady_clock::now().time_since_epoch().count()); int __FAST_IO__ = []() { std::ios::sync_with_stdio(0); std::cin.tie(0); std::cout.tie(0); return 0; }(); #define TESTS int t; cin >> t; while (t--) #define TEST int main() { TEST { int N, K; cin >> N >> K; vi x(N + 1, 0), y(N + 1, 0); REP(i, N) cin >> x[i] >> y[i]; auto dis = [&](int a, int b) { return sqrt((double)(x[a] - x[b]) * (x[a] - x[b]) + (double)(y[a] - y[b]) * (y[a] - y[b])); }; vector dp(1 << N, vvd(N + 1, vd(K + 1, 1e18))); dp[0][N][K] = 0; REP(i, 1 << N) { if (i == 0) { REP(j, N) { dp[1 << j][j][K - 1] = dis(j, N); } } else { REP(j, N + 1) { if (j != N && !(i >> j & 1)) continue; REP(k, K + 1) { REP(l, N + 1) { if (k == 0 && l != N) continue; if (l != N && (i >> l & 1)) continue; chmin(dp[i | (l == N ? 0 : (1 << l))][l][l == N ? K : k - 1], dp[i][j][k] + dis(j, l)); } } } } } double ans = 1e18; REP(i, N) REP(j, K + 1) chmin(ans, dp[(1 << N) - 1][i][j] + dis(i, N)); printf("%.12lf\n", ans); } return 0; }