#include using namespace std; using ll = long long; #define all(a) (a).begin(), (a).end() #define pb push_back #define fi first #define se second mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); const ll MOD1000000007 = 1000000007; const ll MOD998244353 = 998244353; const ll MOD[3] = {999727999, 1070777777, 1000000007}; const ll LINF = 1LL << 60LL; const int IINF = (1 << 30) - 2; template class modint{ long long x; public: modint(long long x=0) : x((x%mod+mod)%mod) {} modint operator-() const { return modint(-x); } bool operator==(const modint& a){ if(x == a) return true; else return false; } bool operator==(long long a){ if(x == a) return true; else return false; } bool operator!=(const modint& a){ if(x != a) return true; else return false; } bool operator!=(long long a){ if(x != a) return true; else return false; } modint& operator+=(const modint& a) { if ((x += a.x) >= mod) x -= mod; return *this; } modint& operator-=(const modint& a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } modint& operator*=(const modint& a) { (x *= a.x) %= mod; return *this; } modint operator+(const modint& a) const { modint res(*this); return res+=a; } modint operator-(const modint& a) const { modint res(*this); return res-=a; } modint operator*(const modint& a) const { modint res(*this); return res*=a; } modint pow(long long t) const { if (!t) return 1; modint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod modint inv() const { return pow(mod-2); } modint& operator/=(const modint& a) { return (*this) *= a.inv(); } modint operator/(const modint& a) const { modint res(*this); return res/=a; } friend std::istream& operator>>(std::istream& is, modint& m) noexcept { is >> m.x; m.x %= mod; if (m.x < 0) m.x += mod; return is; } friend ostream& operator<<(ostream& os, const modint& m){ os << m.x; return os; } }; using mint = modint; void solve(){ int L, K; cin >> L >> K; string s, t; cin >> s >> t; vector a(26); mint sum = 0; for(int i=0; i<26; i++){ cin >> a[i]; sum += mint(a[i]); } vector p(26, 0); for(int i=0; i<26; i++) p[i] = mint(a[i])/sum; vector>> dp(K+1, vector>(K+1, vector(2*L+1, 0))); dp[0][0][L] = 1; for(int i=0; i> T; while(T--) solve(); }