#include #include using namespace boost::multiprecision; constexpr int BSZ = 1024; using UINT = number>; namespace { #pragma GCC diagnostic ignored "-Wunused-function" #include #pragma GCC diagnostic warning "-Wunused-function" using namespace std; using namespace atcoder; #define rep(i,n) for(int i = 0; i < (int)(n); i++) #define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; i--) #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) template bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } else return false; } template bool chmin(T& a, const T& b) { if (b < a) { a = b; return true; } else return false; } using ll = long long; using P = pair; using VI = vector; using VVI = vector; using VL = vector; using VVL = vector; constexpr int M = 1e6 + 100; int lpf[M], phi[M]; void prepare_primes() { memset(lpf, -1, sizeof(lpf)); VI primes; phi[1] = 1; for (int i = 2; i < M; i++) { int p = lpf[i]; if (p == -1) { primes.emplace_back(i); p = lpf[i] = i; phi[i] = i - 1; } for (int q : primes) { int j = i * q; if (j >= M) break; lpf[j] = q; if (q == p) { phi[j] = phi[i] * p; break; } phi[j] = phi[i] * (q - 1); } } } int get_ord(int b, int m) { using mint = modint; modint::set_mod(b); int res = phi[b]; int tmp = res; while (tmp != 1) { int p = lpf[tmp], e = 0, pe = 1; while (tmp % p == 0) tmp /= p, e++, pe *= p; res /= pe; mint m2res = mint(m).pow(res); while (m2res != 1) { res *= p; m2res = m2res.pow(p); } } return res; } int solve(int b, int n, int m) { if (gcd(b, m) != 1) return -1; int t = get_ord(b, m); int c = 0, g = b; while (t != 1) { g = gcd(g, t); if (g == 1) return -1; t /= g; c++; } c = max(c + 1, n); UINT bc = 1; rep(_, c) bc *= b; UINT bcn = bc; rep(_, n) bcn *= b; UINT mbc = [&]() { UINT mbc = 1; auto k = bc; UINT mm = m; while (k) { if (k & 1) mbc = (mbc * mm) % bcn; k >>= 1; mm = (mm * mm) % bcn; } return mbc; }(); auto q = mbc / bc, r = mbc - q * bc; if (r != 1) return -1; return int(q); } } int main() { ios::sync_with_stdio(false); cin.tie(0); prepare_primes(); int tt; cin >> tt; while (tt--) { int b, n, m; cin >> b >> n >> m; cout << solve(b, n, m) << '\n'; } }