N = int(input())

# 残り枠a個にb個入れる通り数
from functools import lru_cache
@lru_cache(maxsize=1000000)
def f(b,a):
    if b > N * a:
        return 0
    if b == 0 or a == 1:
        return 1
    tmp = 0
    for i in range(min(b,N) + 1):
        tmp += f(b - i,a - 1)
    return tmp

print(f(2 * N,8))