#include <iostream> #include <sstream> #include <iomanip> #include <cstring> #include <string> #include <algorithm> #include <cmath> #include <map> #include <set> #include <vector> #include <queue> #include <unordered_set> #include <unordered_map> #include <bitset> #include <ctime> #include <assert.h> #include <deque> #include <list> #include <stack> using namespace std; #define is_mul_overflow(a, b) \ ((b != 0) && (a > LLONG_MAX / b || a < LLONG_MIN / b)) typedef pair<long long, int> pli; typedef pair<int, long long> pil; typedef pair<long long , long long> pll; typedef pair<int, int> pii; typedef pair<double, double> pdd; typedef pair<int, pii> piii; typedef pair<int, long long > pil; typedef pair<long long, pii> plii; typedef pair<double, int> pdi; typedef long long ll; typedef unsigned long long ull; typedef pair<ull, ull> puu; typedef long double ld; const int N = 2000086, MOD = 998244353, INF = 0x3f3f3f3f, MID = 333; const long double EPS = 1e-8; int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1}; // int dx[8] = {1, 1, 0, -1, -1, -1, 0, 1}, dy[8] = {0, 1, 1, 1, 0, -1, -1, -1}; // int dx[8] = {2, 1, -1, -2, -2, -1, 1, 2}, dy[8] = {1, 2, 2, 1, -1, -2, -2, -1}; int n, m, cnt; int w[N]; vector<ll> num; ll res; ll lowbit(ll x) { return x & -x; } ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; } ll lcm(ll a, ll b) { return a / gcd(a, b) * b; } inline double rand(double l, double r) { return (double)rand() / RAND_MAX * (r - l) + l; } inline ll qmi(ll a, ll b, ll c) { ll res = 1; while (b) { if (b & 1) res = res * a % c; a = a * a % c; b >>= 1; } return res; } inline ll qmi(ll a, ll b) { ll res = 1; while (b) { if (b & 1) res *= a; a *= a; b >>= 1; } return res; } inline double qmi(double a, ll b) { double res = 1; while (b) { if (b & 1) res *= a; a *= a; b >>= 1; } return res; } // inline ll C(ll a, ll b) { if (a < b) return 0; if (b > a - b) b = a - b; ll res = 1; for (ll i = 1, j = a; i <= b; i++, j--) { res = res * (j % MOD) % MOD; res = res * qmi(i, MOD - 2, MOD) % MOD; } return res; } inline ll C(ll a, ll b, int* c) { if (a < b) return 0; ll res = 1; for (ll j = a, i = 1; i < b + 1; i++, j--) res *= j; for (ll j = a, i = 1; i < b + 1; i++, j--) res /= i; return res; } inline int find_(int x) { return lower_bound(num.begin(), num.end(), x) - num.begin(); } int a[11][11], b[11][11], t[11][11], tar[6][11][11]; vector<pair<char, int> > ans; bool check(int a[11][11], int b[11][11]) { for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) if (a[i][j] != b[i][j]) return 0; return 1; } bool dfs(int t[11][11], int c) { if (c == m) { for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) if (t[i][j] != a[i][j]) return 0; return 1; } int tmp[11][11], t2[11][11]; for (int p = 1; p < n + 1; p++) { ans.push_back({'R', t[p][p]}); memcpy(tmp, t, sizeof tmp); memcpy(t2, tmp, sizeof t2); for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) tmp[t2[p][i]][j] = t2[i][j]; if (dfs(tmp, c + 1)) { for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) tar[c + 1][i][j] = tmp[i][j]; return 1; } ans.pop_back(); } for (int p = 1; p < n + 1; p++) { ans.push_back({'C', t[p][p]}); memcpy(tmp, t, sizeof tmp); memcpy(t2, tmp, sizeof t2); for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) tmp[i][t2[j][p]] = t2[i][j]; if (dfs(tmp, c + 1)) { for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) tar[c + 1][i][j] = tmp[i][j]; return 1; } ans.pop_back(); } return 0; } inline void solve() { dfs(t, 0); vector<pair<char, int> > res; memcpy(tar[0], b, sizeof tar[0]); for (int i = m - 1; i > -1; i--) { auto u = ans.back(); ans.pop_back(); if (u.first == 'R') { int ne = u.second; while (!check(tar[i], a)) { res.push_back({'R', ne}); memcpy(t, a, sizeof t); for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) a[t[ne][i]][j] = t[i][j]; ne = t[ne][ne]; } } else { int ne = u.second; while (!check(tar[i], a)) { res.push_back({'C', ne}); memcpy(t, a, sizeof t); for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) a[i][t[j][ne]] = t[i][j]; ne = t[ne][ne]; } } } printf("%d\n", res.size()); for (auto u : res) printf("%c %d\n", u.first, u.second); } int main() { cin >> n >> m; for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) scanf("%d", b[i] + j); for (int i = 1; i < n + 1; i++) for (int j = 1; j < n + 1; j++) scanf("%d", a[i] + j), t[i][j] = b[i][j]; solve(); return 0; }