#include using namespace std; using ll=long long; using ld=long double; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} struct point{ ll x; ll y; }; ll dist(point a, point b){ return (a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y); } void solve(); // CITRUS CURIO CITY / FREDERIC int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; // cin >> t; rep(i, 0, t) solve(); } void solve(){ vector p(4); rep(i, 0, 4) cin >> p[i].x >> p[i].y; int ans1 = 0, ans2 = 0, ans3 = 0; auto my_cos = [&](point a, point b, point c) -> pair { return {dist(a, b) + dist(a, c) - dist(b, c), 4ll * dist(a, b) * dist(a, c)}; }; auto f = [&](point a, point b, point c, point d) -> void { auto A = my_cos(c, a, b); auto B = my_cos(d, a, b); if (A.first * A.first == A.second) ans1 = INF; if (B.first * B.first == B.second) ans1 = INF; if (A.first * A.first * B.second == B.first * B.first * A.second){ if (A.first == 0) ans3 = 1; else if ((A.first < 0) ^ (B.first < 0)) ans2++; else ans1++; } }; f(p[0], p[1], p[2], p[3]); f(p[0], p[2], p[3], p[1]); f(p[0], p[3], p[1], p[2]); f(p[1], p[2], p[0], p[3]); f(p[1], p[3], p[0], p[2]); f(p[2], p[3], p[0], p[1]); yneos((ans1 == 4 && ans2 == 2) || ans3 == 1, true); }