#include using namespace std; using ll = long long; #define all(a) (a).begin(), (a).end() #define pb push_back #define fi first #define se second mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); const ll MOD1000000007 = 1000000007; const ll MOD998244353 = 998244353; const ll MOD[3] = {999727999, 1070777777, 1000000007}; const ll LINF = 1LL << 60LL; const int IINF = (1 << 30) - 2; ll dist(pair x, pair y){ return (x.fi-y.fi)*(x.fi-y.fi) + (x.se-y.se)*(x.se-y.se); } ll pow2(ll n){ return n*n; } void solve(){ vector> P(4); for(int i=0; i<4; i++) cin >> P[i].fi >> P[i].se; {//凸包構築 sort(all(P)); vector> U, L; for(int i=0; i<4; i++){ while(U.size() >= 2 && (U[U.size()-1].fi-U[U.size()-2].fi)*(P[i].se-U[U.size()-2].se) <= (P[i].fi-U[U.size()-2].fi)*(U[U.size()-1].se-U[U.size()-2].se)) U.pop_back(); while(L.size() >= 2 && (L[L.size()-1].fi-L[L.size()-2].fi)*(P[i].se-L[L.size()-2].se) >= (P[i].fi-L[L.size()-2].fi)*(L[L.size()-1].se-L[L.size()-2].se)) L.pop_back(); U.pb(P[i]); L.pb(P[i]); } P.clear(); for(int i=0; i0; i--) P.pb(L[i]); } if((int)P.size() != 4){ cout << "NO\n"; return; } ll ab = dist(P[0], P[1]); ll cd = dist(P[2], P[3]); ll ad = dist(P[0], P[3]); ll bc = dist(P[1], P[2]); ll ac = dist(P[0], P[2]); ll bd = dist(P[1], P[3]); if(4LL*ab*cd*ad*bc == pow2(ac*bd-ab*cd-ad*bc)){ cout << "YES\n"; return; } cout << "NO\n"; } int main(){ cin.tie(nullptr); ios::sync_with_stdio(false); int T=1; //cin >> T; while(T--) solve(); }