// TLE想定 O(M*2^n)解 #include // all using namespace std; #define MAX_T 10000 #define MAX_N 27 #define MAX_COST 1e8 expected, vector> is_sorting_network(const int n, const vector> cmps) { using stat = uint64_t; assert(2 <= n && n <= MAX_N && MAX_N <= numeric_limits::digits); for (auto [a, b] : cmps) { // 0-indexed assert(0 <= a && a < b && b < n); } int m = cmps.size(); vector unused(m, true), unsorted(n - 1, false); for (stat i = ((~(stat)1) << (n - 1)); i != 0; i++) { stat state = i; for (int j = 0; auto [a, b] : cmps) { if (((state >> a) & 1) > ((state >> b) & 1)) { unused[j] = false; state ^= ((stat)1 << a) | ((stat)1 << b); } ++j; } if (countl_one(state) + countr_zero(state) < numeric_limits::digits) { for (int j = 0; j < n - 1; ++j) { if (((state >> j) & 3) == 1) { unsorted[j] = true; } } } } if (any_of(unsorted.begin(), unsorted.end(), [](bool x) { return x; })) { return unexpected(unsorted); } return unused; } int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); int t; cin >> t; assert(1 <= t && t <= MAX_T); // phi = (1 + sqrt(5)) / 2 : golden ratio double phi = sqrt(1.25) + 0.5; // testcases cost <= 1e8 double cost = 0.0; for (int i = 0; i < t; ++i) { int n, m; cin >> n >> m; vector> cmps; assert(2 <= n && n <= MAX_N && 1 <= m && m <= n * (n - 1) / 2); cost += m * pow(phi, n); assert(cost <= MAX_COST); vector vec_a, vec_b; for (int j = 0; j < m; ++j) { int a; cin >> a; vec_a.push_back(a); } for (int j = 0; j < m; ++j) { int b; cin >> b; vec_b.push_back(b); } for (int j = 0; j < m; ++j) { int a = vec_a[j], b = vec_b[j]; assert(1 <= a && a < b && b <= n); // 1-indexed to 0-indexed cmps.emplace_back(a - 1, b - 1); } auto is_sorting = is_sorting_network(n, cmps); if (is_sorting.has_value()) { auto unused = is_sorting.value(); assert(unused.size() == m); cout << "Yes\n"; cout << count(unused.begin(), unused.end(), true) << '\n'; // 1-indexed for (int j = 1; const auto x : unused) { if (x) { cout << j << ' '; } j++; } cout << '\n'; } else { auto unsorted = is_sorting.error(); assert(unsorted.size() == n - 1); cout << "No\n"; cout << count(unsorted.begin(), unsorted.end(), true) << '\n'; // 1-indexed for (int j = 1; const auto x : unsorted) { if (x) { cout << j << ' '; } j++; } cout << '\n'; } } return 0; }