#include using namespace std; #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #define rep(i,a,b) for(int i=a;i=b;i--) #define fore(i,a) for(auto &i:a) #define all(a) begin(a),end(a) #define allr(a) rbegin(a),rend(a) #define pb push_back #define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end()) using ll =long long; using pii = pair; using pll = pair; using vi= vector; using vll =vector; using vvi = vector>; inline bool ingrid(int a,int b,int h,int w){ return 0<=a&&a inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; } int popcount(int t){return __builtin_popcount(t);} int popcount(ll t){return __builtin_popcountll(t);} struct Edge{ int from,to;ll cost;int idx; Edge()=default; Edge(int from,int to,ll cost=1,int idx=-1):from(from),to(to),cost(cost),idx(idx){} operator int() const {return to;} }; constexpr pii dx4[4]={{0,1},{0,-1},{1,0},{-1,0}}; constexpr pii dx[100]={}; #define endl '\n' #include int main(){ cin.tie(nullptr); ios::sync_with_stdio(false); int n,m;cin>>n>>m; vi x,y;x.resize(m);y.resize(m); vector> g(n); rep(i,0,m){ cin>>x[i]>>y[i]; x[i]--;y[i]--; g[x[i]].insert(y[i]); g[y[i]].insert(x[i]); } vll A(n); rep(i,0,n){ cin>>A[i]; } int B=300; int q; cin>>q; vector cur;//今見ている頂点 vll ans(n);//差分更新しながら使う vector> event; rep(i,0,q){ int t; cin>>t; if(t==1){ int u,v;cin>>u>>v;u--;v--; event.emplace_back(t,u,v); }else if(t==2){ int p;ll a;cin>>p>>a;p--; event.emplace_back(t,p,a); }else{ int c;int tmp=-1;cin>>c;c--; event.emplace_back(t,c,tmp); } } rep(i,0,q){ if(i%B==0){ //初期化 cur.clear(); rep(j,0,n){ ans[j]=0; fore(k,g[j]){ ans[j]+=A[k]; } } rep(j,i,min(q,i+B)){ int t,u,v;tie(t,u,v)=event[j]; if(t==3){ cur.pb(u); } } UNIQUE(cur); } int t,u,v;tie(t,u,v)=event[i]; if(t==1){ if(g[u].find(v)!=g[u].end()){ g[u].erase(v); g[v].erase(u); ans[u]-=A[v]; ans[v]-=A[u]; }else{ g[u].insert(v); g[v].insert(u); ans[u]+=A[v]; ans[v]+=A[u]; } }else if(t==2){ int p=u;ll a=v; fore(j,cur){ if(g[p].find(j)!=g[u].end()){ ans[j]-=A[p]; ans[j]+=v; } } A[p]=v; }else{ cout<