#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;} template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} // Square Division // Divide into D setions // l[0] = 0, r[i] = l[i + 1], r[D - 1] = N // [l[i], r[i]) // divide [lq, rq) // if [lq, rq) is in a single section // [[lq, lq + 1, ..., rq - 1], [], []] // else // [[lq, lq + 1, ..., r[a - 1] - 1], [a, a + 1, ..., b - 1], [l[b], l[b] + 1, ..., rq - 1]] struct SquareDivision{ int n, D; vector<int> l, r; SquareDivision(int n, int D = -1) : n(n), D(D) {} bool initialized = false; void init(){ assert(n > 0); initialized = true; if(D == -1) D = sqrt(n); assert(D >= 1 and D <= n); l.resize(D); r.resize(D); l[0] = 0; int width = n / D; assert(width > 0); rep(i, D - 1){ r[i] = l[i] + width; l[i + 1] = r[i]; } r[D - 1] = n; } tuple<vector<int>, vector<int>, vector<int>> divide(int lq, int rq){ vector<int> minor_left; vector<int> major; vector<int> minor_right; int i = lower_bound(l.begin(), l.end(), lq) - l.begin(); { int next; if(i == D) next = n; else next = l[i]; if(rq <= next){ for(int idx = lq; idx < rq; idx++) minor_left.push_back(idx); return make_tuple(minor_left, major, minor_right); }else{ for(int idx = lq; idx < next; idx++) minor_left.push_back(idx); } } for(; i < D; i++){ if(r[i] <= rq){ major.push_back(i); }else{ for(int idx = l[i]; idx < rq; idx++){ minor_right.push_back(idx); } return make_tuple(minor_left, major, minor_right); } } return make_tuple(minor_left, major, minor_right); } }; int main(){ int n, m; cin >> n >> m; vector<unordered_set<int>> G(n); rep(i, m){ int u, v; cin >> u >> v; u--; v--; G[u].insert(v); G[v].insert(u); } vector<long long> a(n); cin >> a; int q; cin >> q; vector<tuple<int, int, int>> Query; rep(i, q){ int t, var1, var2; cin >> t; if(t == 1){ cin >> var1 >> var2; var1--; var2--; } if(t == 2){ cin >> var1 >> var2; var1--; } if(t == 3){ cin >> var1; var1--; } Query.emplace_back(t, var1, var2); } int D = max(1, int(sqrt(q) / 2)); SquareDivision sq(q, D); sq.init(); rep(i, D){ map<int, long long> s; vector<int> list; for(int j = sq.l[i]; j < sq.r[i]; j++){ auto [t, var1, var2] = Query[j]; if(t == 3) list.push_back(var1); } sort(list.begin(), list.end()); list.erase(unique(list.begin(), list.end()), list.end()); for(int u : list){ s[u] = 0; for(int v : G[u]){ s[u] += a[v]; } } for(int j = sq.l[i]; j < sq.r[i]; j++){ auto [t, var1, var2] = Query[j]; if(t == 1){ if(G[var1].find(var2) == G[var1].end()){ G[var1].insert(var2); G[var2].insert(var1); if(s.find(var1) != s.end()) s[var1] += a[var2]; if(s.find(var2) != s.end()) s[var2] += a[var1]; }else{ G[var1].erase(var2); G[var2].erase(var1); if(s.find(var1) != s.end()) s[var1] -= a[var2]; if(s.find(var2) != s.end()) s[var2] -= a[var1]; } } if(t == 2){ for(int v : list){ if(G[v].find(var1) != G[v].end()) s[v] += var2 - a[var1]; } a[var1] = var2; } if(t == 3){ cout << s[var1] << "\n"; } } } return 0; }