#include <iostream>
#include <math.h>
#include <algorithm>
using namespace std;
typedef long long ll;
int main() {
	ll n;	cin >> n;
	//(a+1)(b+1)(c+1)=Nを満たす中でのa+b+cの最小値
	ll ans = 1e9;
	for (ll a = ceil(cbrt(n)); a > 0; a--) {
		if (n%a != 0)	continue;
		ll left = n / a;
		for (ll b = sqrt(left); b > 0; b--) {
			if (left%b != 0)	continue;
			ll c = left / b;
			ans = min(a + b + c - 3, ans);
		}
	}
	cout << ans << " " << n - 1 << endl;
	return 0;
}