#include using namespace std; #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #define rep(i,a,b) for(int i=a;i=b;i--) #define fore(i,a) for(auto &i:a) #define pb push_back #define all(a) begin(a),end(a) #define allr(a) rbegin(a),rend(a) #define ff first #define ss second template bool chmax(T& a,T b){return a bool chmin(T& a,T b){return a>b?a=b,1:0;} using ll =long long; using pii =pair; using pll=pair; using vi=vector; using vll=vector; inline bool ingrid(int a,int b,int h,int w){ return 0<=a&&a::max() / 2; const long long INFL = numeric_limits::max() / 2; constexpr pii dx4[4] = {pii{-1, 0}, pii{0, -1},pii{1, 0}, pii{0, 1} }; #define endl '\n' ll x,n; void solve(){ if(x<=0){ ll ok=0,ng=n+1; while(abs(ok-ng)>1){ ll mid=(ok+ng)/2; double p=mid;p=p*(p+1)/2; if(p>=1e19)ng=mid; else if(((mid&1)?(mid+1)/2*mid:mid/2*(mid+1))+x<=0)ok=mid; else ng=mid; } ll ans=((ok&1)?(ok+1)/2*ok:ok/2*(ok+1))+x; ans-=(n-ok)/2; if((n-ok)&1){ ans+=n; } cout<1){ ll mid=(ok+ng)/2; double p=mid;p=p*(p+1)/2; if(p>=1e19)ng=mid; else if(x-((mid&1)?(mid+1)/2*mid:mid/2*(mid+1))>0)ok=mid; else ng=mid; } ll ans=x-((ok&1)?(ok+1)/2*ok:ok/2*(ok+1)); ans+=(n-ok)/2; if((n-ok)&1){ ans-=n; } cout<>x>>n; solve(); return 0; } /* */