#include #include #define rep(i,n) for(int i=0;i vi; typedef vector vl; typedef vector> vvi; typedef vector> vvl; typedef long double ld; typedef pair P; template ostream& operator<<(ostream& os, const static_modint& a) {os << a.val(); return os;} template ostream& operator<<(ostream& os, const dynamic_modint& a) {os << a.val(); return os;} template istream& operator>>(istream& is, static_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, dynamic_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, vector& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template ostream& operator<<(ostream& os, const pair& p){os << p.first << ' ' << p.second; return os;} template ostream& operator<<(ostream& os, const vector& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const vector>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template ostream& operator<<(ostream& os, const set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const unordered_set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const atcoder::segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const atcoder::lazy_segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template void chmin(T& a, T b){a = min(a, b);} template void chmax(T& a, T b){a = max(a, b);} int main(){ long long x, n; cin >> x >> n; long long ng = -1, ok = 2002002002; while(ok - ng > 1){ long long mid = (ok + ng) / 2; long long diff = mid * (mid + 1) / 2; if(x > 0){ if(x - diff <= 0) ok = mid; else ng = mid; }else{ if(x + diff > 0) ok = mid; else ng = mid; } } if(n <= ok){ long long diff = n * (n + 1) / 2; if(x > 0){ cout << x - diff << "\n"; }else{ cout << x + diff << "\n"; } return 0; } long long y = 0; { long long diff = ok * (ok + 1) / 2; if(x > 0){ y = x - diff; }else{ y = x + diff; } assert(abs(y) <= ok); } if((n - ok) % 2){ ok ++; if(y <= 0) y += ok; else y -= ok; } { long long ans = y; if(y <= 0) ans -= (n - ok) / 2; else ans += (n - ok) / 2; cout << ans << "\n"; } return 0; }