#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using namespace atcoder; typedef long long ll; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--) #define repk(i, k, n) for (int i = k; i < (int)(n); i++) #define all(v) v.begin(), v.end() #define vi vector #define vs vector #define vc vector #define vl vector #define vb vector #define vvi vector> #define vvc vector> #define vvl vector> #define vvb vector> #define vvvi vector>> #define vvvl vector>> #define pii pair #define pil pair #define pli pair #define pll pair #define vpii vector> #define vpll vector> #define vvpii vector>> #define vvpll vector>> template void debug(T e) { cerr << e << endl; } template void debug(vector &v) { rep(i, v.size()) { cerr << v[i] << " "; } cerr << endl; } template void debug(vector> &v) { rep(i, v.size()) { rep(j, v[i].size()) { cerr << v[i][j] << " "; } cerr << endl; } } template void debug(vector> &v) { rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; } } template void debug(set &st) { for (auto itr = st.begin(); itr != st.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template void debug(multiset &ms) { for (auto itr = ms.begin(); itr != ms.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template void debug(map &mp) { for (auto itr = mp.begin(); itr != mp.end(); itr++) { cerr << itr->first << " " << itr->second << endl; } } void debug_out() { cerr << endl; } template void debug_out(Head H, Tail... T) { cerr << H << " "; debug_out(T...); } using mint = modint998244353; int main() { int H, W, A, B; cin >> H >> W >> A >> B; mint ans = 2 * A * B; // 各マスに対して、2 回とも塗られる確率を求めてそれを引くと期待値となる // 縦と横が実は独立っぽいのでそうやって考えたい mint bumbo = mint(H - A + 1) * mint(W - B + 1); bumbo = bumbo * bumbo; mint tate = 0; for (int i = 1; i <= H; i++) { int prod = min(i, H + 1 - i); prod = min(prod, A); tate += mint(prod) * mint(prod); } mint yoko = 0; for (int i = 1; i <= W; i++) { int prod = min(i, W + 1 - i); prod = min(prod, B); yoko += mint(prod) * mint(prod); } ans -= (tate * yoko / bumbo); cout << ans.val() << endl; }