import sys from collections import deque sys.setrecursionlimit(1 << 25) def main(): input = sys.stdin.read().split() idx = 0 N, Q = int(input[idx]), int(input[idx+1]) idx += 2 adj = [[] for _ in range(N+1)] for _ in range(N-1): a = int(input[idx]) b = int(input[idx+1]) adj[a].append(b) adj[b].append(a) idx += 2 depth = [0] * (N + 1) parent = [0] * (N + 1) q = deque([1]) depth[1] = 0 parent[1] = 0 while q: u = q.popleft() for v in adj[u]: if v != parent[u] and depth[v] == 0: depth[v] = depth[u] + 1 parent[v] = u q.append(v) LOG = 20 up = [[0] * (N + 1) for _ in range(LOG)] up[0] = parent for k in range(1, LOG): for v in range(1, N + 1): up[k][v] = up[k-1][up[k-1][v]] size = [1] * (N + 1) stack = [(1, False)] while stack: u, visited = stack.pop() if visited: for v in adj[u]: if v != parent[u]: size[u] += size[v] continue stack.append((u, True)) for v in adj[u]: if v != parent[u]: stack.append((v, False)) edge_map = {} for u in range(1, N+1): for v in adj[u]: if depth[u] < depth[v]: s = size[v] edge_map[(u, v)] = s edge_map[(v, u)] = N - s else: s = size[u] edge_map[(v, u)] = s edge_map[(u, v)] = N - s def lca(u, v): if depth[u] < depth[v]: u, v = v, u for k in reversed(range(LOG)): if depth[u] - (1 << k) >= depth[v]: u = up[k][u] if u == v: return u for k in reversed(range(LOG)): if up[k][u] != up[k][v]: u = up[k][u] v = up[k][v] return parent[u] def get_kth(u, k): current = u for i in range(LOG): if k & (1 << i): current = up[i][current] if current == 0: return 0 return current output = [] for _ in range(Q): S = int(input[idx]) T = int(input[idx+1]) idx += 2 L = lca(S, T) dS = depth[S] - depth[L] dT = depth[T] - depth[L] D = dS + dT if D % 2 != 0: output.append('0') continue k = D // 2 if k <= dS: M = get_kth(S, k) else: M = get_kth(T, (dS + dT) - k) if k == 0: u = S else: u = get_kth(S, k - 1) steps_t = (D - k) - 1 if steps_t < 0: v = T else: v = get_kth(T, steps_t) a = edge_map.get((M, u), 0) b = edge_map.get((M, v), 0) ans = N - a - b output.append(str(ans)) print('\n'.join(output)) if __name__ == '__main__': main()