#include using namespace std; #include #define rep(i, l, r) for (int i = (int)(l); i<(int)(r); i++) #define ll long long struct Mo { int width; vector left, right, order; Mo(int N, int Q) : order(Q) { width = max(1, 1.0 * N / max(1.0, sqrt(Q * 2.0 / 3.0))); iota(begin(order), end(order), 0); } void insert(int l, int r) { /* [l, r) */ left.emplace_back(l); right.emplace_back(r); } template void run(const AL &add_left, const AR &add_right, const DL &delete_left, const DR &delete_right, const REM &rem) { assert(left.size() == order.size()); sort(begin(order), end(order), [&](int a, int b) { int ablock = left[a] / width, bblock = left[b] / width; if (ablock != bblock) return ablock < bblock; if (ablock & 1) return right[a] < right[b]; return right[a] > right[b]; }); int nl = 0, nr = 0; for (auto idx : order) { while (nl > left[idx]) add_left(--nl); while (nr < right[idx]) add_right(nr++); while (nl < left[idx]) delete_left(nl++); while (nr > right[idx]) delete_right(--nr); rem(idx); } } }; /** * @brief Mo's algorithm * @docs docs/misc/mo.md */ int main() { // freopen("in.txt", "r", stdin); // freopen("out.txt", "w", stdout); int N, Q; cin >> N >> Q; vector A(N); rep(i, 0, N) cin >> A[i]; Mo mo(N, Q); vector L(Q), R(Q); vector X(Q); rep(i, 0, Q) { cin >> L[i] >> R[i]; cin >> X[i]; L[i]--; mo.insert(L[i], R[i]); } vector C = A; C.insert(C.end(), X.begin(), X.end()); sort(C.begin(), C.end()); vector B(N); rep(i, 0, N) B[i] = lower_bound(C.begin(), C.end(), A[i]) - C.begin(); vector Y(Q); rep(i, 0, Q) Y[i] = lower_bound(C.begin(), C.end(), X[i]) - C.begin(); // for (int v : B) cout << v << " "; // cout << endl; // for (int v : Y) cout << v << " "; // cout << endl; atcoder::fenwick_tree F(N+Q); atcoder::fenwick_tree G(N+Q); auto add = [&](int x) -> void { F.add(B[x], A[x]); G.add(B[x], 1); }; auto del = [&](int x) -> void { F.add(B[x], -A[x]); G.add(B[x], -1); }; vector ANS(Q); auto rem = [&](int id) -> void { ll ans = 0; { ans += F.sum(Y[id], N+Q); ans -= G.sum(Y[id], N+Q) * X[id]; } { ans += G.sum(0, Y[id]) * X[id]; ans -= F.sum(0, Y[id]); } ANS[id] = ans; }; mo.run(add, add, del, del, rem); rep(i, 0, Q) cout << ANS[i] << endl; }