S = input().strip()
unique_chars = list(set(S))

# Since the problem states there are exactly two unique characters, we can safely proceed
count = {}
for c in S:
    count[c] = count.get(c, 0) + 1

# Find which character has a count of 1
target_char = unique_chars[0] if count[unique_chars[0]] == 1 else unique_chars[1]

# Find the 1-based index of the target character
for idx, c in enumerate(S, 1):
    if c == target_char:
        print(f"{idx} {c}")
        break