#include #define rep(i, p, n) for (ll i = p; i < (ll)(n); i++) #define rep2(i, p, n) for (ll i = p; i >= (ll)(n); i--) using namespace std; using ll = long long; using ld = long double; const double pi = 3.141592653589793; const long long inf = 2 * 1e9; const long long linf = 4 * 1e18; const ll mod1 = 1000000007; const ll mod2 = 998244353; template inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T &a, T b) { if (a > b) { a = b; return 1; } return 0; } // atcoder #include using namespace atcoder; using mint1 = modint1000000007; using mint2 = modint998244353; vector> base = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; int main() { ////////////////// ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); ////////////////// ll N, M; cin >> N >> M; vector A(N); map ma; map ch; rep(i, 0, N) { cin >> A.at(i); A.at(i) %= M; ma[A.at(i)]++; // cout << A.at(i) << endl; } ll ans = 0; rep(i, 0, N) { if (ch[A.at(i)]) { continue; } if (M%2==0 && A.at(i)==M/2) { ans++; } else if (A.at(i)==0) { ans++; } else { ans += max(ma[A.at(i)], ma[(M - A.at(i)) % M]); } ch[A.at(i)] = true; ch[(M - A.at(i)) % M] = true; } cout << ans; }