#include #include #define rep(i,n) for(int i=0;i P; template ostream& operator<<(ostream& os, const static_modint& a) {os << a.val(); return os;} template ostream& operator<<(ostream& os, const dynamic_modint& a) {os << a.val(); return os;} template istream& operator>>(istream& is, static_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, dynamic_modint& a) {long long x; is >> x; a = x; return is;} template istream& operator>>(istream& is, vector& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template ostream& operator<<(ostream& os, const pair& p){os << p.first << ' ' << p.second; return os;} template ostream& operator<<(ostream& os, const vector& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const vector>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template ostream& operator<<(ostream& os, const set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const unordered_set& se){for(T x : se) os << x << " "; os << "\n"; return os;} template ostream& operator<<(ostream& os, const atcoder::segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template ostream& operator<<(ostream& os, const atcoder::lazy_segtree& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template void chmin(T& a, T b){a = min(a, b);} template void chmax(T& a, T b){a = max(a, b);} int main(){ int n; cin >> n; auto solve_even = [&](int n){ int cnt = 1; vector> s(n, vector(n)); for(int i = 0; i < n / 2; i++){ if(i % 2 == 0){ for(int j = 0; j < n / 2; j++){ s[2 * i][2 * j] = cnt; s[2 * i + 1][2 * j + 1] = cnt + 1; s[2 * i + 1][2 * j] = cnt + 2; s[2 * i][2 * j + 1] = cnt + 3; cnt += 4; } }else{ for(int j = n / 2 - 1; j >= 0; j--){ s[2 * i][2 * j + 1] = cnt; s[2 * i + 1][2 * j] = cnt + 1; s[2 * i + 1][2 * j + 1] = cnt + 2; s[2 * i][2 * j] = cnt + 3; cnt += 4; } } } return s; }; if(n % 2 == 0){ auto s = solve_even(n); cout << s; }else{ assert(false); } return 0; }