#include #include using namespace std; using namespace atcoder; typedef long long ll; typedef unsigned long long ull; typedef long double ld; #define rep(i, n) for (ll i = 0; i < (ll)(n); i++) #define rrep(i,start,end) for (ll i = start;i >= (ll)(end);i--) #define repn(i,end) for(ll i = 0; i <= (ll)(end); i++) #define reps(i,start,end) for(ll i = start; i < (ll)(end); i++) #define repsn(i,start,end) for(ll i = start; i <= (ll)(end); i++) #define each(p,a) for(auto &p:a) typedef vector vll; typedef vector> vpll; typedef vector> vvll; typedef set sll; typedef map mpll; typedef pair pll; typedef tuple tpl3; #define LL(...) ll __VA_ARGS__; input(__VA_ARGS__) #define LD(...) ld __VA_ARGS__; input(__VA_ARGS__) #define Str(...) string __VA_ARGS__; input(__VA_ARGS__) #define Ch(...) char __VA_ARGS__; input(__VA_ARGS__) #define all(a) (a).begin(),(a).end() #define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() ); #define sz(x) (ll)x.size() // << std::fixed << std::setprecision(10) const ll INF = 1LL << 60; const ld EPS = 1e-9; inline ll lfloor(ll x,ll m){return (x - ((x % m+ m)%m))/m;} inline ll positive_mod(ll a,ll m){return (a % m + m)%m;} inline ll popcnt(ull a){ return __builtin_popcountll(a);} //0indexed inline ll topbit(ll a){assert(a != 0);return 63 - __builtin_clzll(a);} inline ll smlbit(ll a){assert(a != 0);return __builtin_ctzll(a);} template bool chmin(T& a, T b){if(a > b){a = b;return true;}return false;} template bool chmax(T& a, T b){if(a < b){a = b;return true;}return false;} template std::istream &operator>>(std::istream&is,std::vector&v){for(T &in:v){is>>in;}return is;} template std::ostream &operator<<(std::ostream&os,const std::vector&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?" ":"");}return os;} templatestd::ostream &operator<< (std::ostream &os, std::pair p){os << "{" << p.first << "," << p.second << "}";return os;} templatevoid input(T&... a){(cin >> ... >> a);} void print(){cout << endl;} templatevoid print(const T& a, const Ts&... b){cout << a;((cout << ' ' << b), ...);cout << endl;} template void pspace(const T& a){ cout << a << ' ';} void perr(){cerr << endl;} templatevoid perr(const T& a, const Ts&... b){cerr << a;((cerr << ' ' << b), ...);cerr << endl;} void yes(bool i = true){ return print(i?"yes":"no"); } void Yes(bool i = true){ return print(i?"Yes":"No"); } void YES(bool i = true){ return print(i?"YES":"NO"); } template vector &operator++(vector &v) {for(auto &e : v) e++;return v;} template vector operator++(vector &v, signed) {auto res = v;for(auto &e : v) e++;return res;} template vector &operator--(vector &v) {for(auto &e : v) e--;return v;} template vector operator--(vector &v, signed) {auto res = v;for(auto &e : v) e--;return res;} //grid探索用 vector _ta = {0,0,1,-1,1,1,-1,-1}; vector _yo = {1,-1,0,0,1,-1,1,-1}; bool isin(ll now_i,ll now_j,ll h,ll w){return (0<=now_i && now_i < h && 0 <= now_j && now_j < w);} ll lpow(ll x,ll n){ll ans = 1;while(n >0){if(n & 1)ans *= x;x *= x;n >>= 1;}return ans;} ll Modlpow(ll x,ll n,ll m){ll ans = 1;ll a = x%m;while(n >0){if(n & 1){ans *= a;ans%= m;}a *= a;a %= m;n >>= 1;}return ans;} const ll MOD9 = 998244353LL; const ll MOD10 = 1000000007LL; //最強,前処理(n), 計算(1) //n,k <= 10^7の時 const ll MOD = 998244353; vector fact, fact_inv, inv; /* init_nCk :二項係数のための前処理 計算量:O(n) */ void init_nCk(ll SIZE) { fact.resize(SIZE + 5); fact_inv.resize(SIZE + 5); inv.resize(SIZE + 5); fact[0] = fact[1] = 1; fact_inv[0] = fact_inv[1] = 1; inv[1] = 1; for (int i = 2; i < SIZE + 5; i++) { fact[i] = fact[i - 1] * i % MOD; inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;//iの逆元 fact_inv[i] = fact_inv[i - 1] * inv[i] % MOD;//i!の逆元 } } /* nCk :MODでの二項係数を求める(前処理 int_nCk が必要) 計算量:O(1) */ long long nCk(ll n, ll k) { assert(!(n < k)); assert(!(n < 0 || k < 0)); return fact[n] * (fact_inv[k] * fact_inv[n - k] % MOD) % MOD; } int main(){ ios::sync_with_stdio(false);cin.tie(nullptr); init_nCk(lpow(10,6)); LL(n); Str(s); if(s[1] == ')'){ n /= 2; cout << Modlpow(2,n,MOD9) << endl; }else{ n/=2; using mint = modint998244353; mint ans = 0; repn(i,n){ ans += nCk(n,i) * nCk(n,i); } cout << ans.val() << endl; } }