n, m, c = map(int, input().split())

# Calculate the position (X, Y) of channel C
x = (c - 1) // m + 1
y = (c - 1) % m + 1

# Check if the grid is 1x1 (but according to problem statement, at least one of N or M is >=2)
# So no need to handle 1x1 case.

# Check if the grid is single row or column
if n == 1 or m == 1:
    if n * m == 2:
        print("YES")
    else:
        print("NO")
else:
    # Check if either dimension is even
    if n % 2 == 0 or m % 2 == 0:
        print("YES")
    else:
        # Both are odd, check if C is at a corner
        is_corner = (x == 1 or x == n) and (y == 1 or y == m)
        if is_corner:
            print("NO")
        else:
            print("YES")