implicit none
  integer::N,i,j
  integer,allocatable::L(:,:)
  integer::total(6),max,indx
  data total/6*0/
  read *,N
  allocate(L(N,0:6))
  read *,L(:,0)

  do i=1,N
     L(i,6) = L(i,0)/6
     L(i,5) = L(i,0)/5
     L(i,4) = L(i,0)/4
     L(i,3) = L(i,0)/3
     L(i,2) = L(i,0)/2
     L(i,1) = L(i,0)
  end do

  total(6) = SUM(L(:,6))
  total(5) = SUM(L(:,5))-total(6)
  total(4) = SUM(L(:,4))-total(6)-total(5)
  total(3) = SUM(L(:,3))-2*total(6)-total(5)-total(4)
  total(2) = SUM(L(:,2))-3*total(6)-2*total(5)-2*total(4)-total(3)
  total(1) = N-SUM(total(2:6))
  max = MAXVAL(total(1:6))

  do i=6,1,-1
     if(max.eq.total(i)) then
        print '(i0)', i
        return
     end if
  end do
end program