#include <bits/stdc++.h>
using namespace std;
using int64 = long long;

// Compute x^e mod m in O(log e)
int64 modpow(int64 x, int64 e, int64 m) {
    int64 res = 1 % m;
    x %= m;
    while (e > 0) {
        if (e & 1) res = (__int128)res * x % m;
        x = (__int128)x * x % m;
        e >>= 1;
    }
    return res;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int T;
    cin >> T;
    while (T--) {
        int64 A, B, C;
        cin >> A >> B >> C;
        // We want the C-th digit after the decimal point of A/B.
        // Let r = (A * 10^{C-1} mod B). Then the digit is floor(r*10 / B).
        int64 pow10 = modpow(10, C - 1, B);
        int64 r = (__int128)A * pow10 % B;
        int64 digit = (r * 10) / B;
        cout << digit << "\n";
    }
    return 0;
}