#include //#include using namespace std; //using namespace atcoder; #define all(v) v.begin(),v.end() using ll = long long; using ull = unsigned long long; using lll = __int128; using vll=vector; using vvll = vector>; using P = pair; using vp=vector>; //using mint=modint1000000007; //using mint=modint998244353; const ll INF=1ll<<60; ll mod10=1e9+7; ll mod99=998244353; const double PI = acos(-1); #define rep(i,n) for (ll i=0;i=0;--i) #define rep2(i,a,n) for (ll i=a;i=n;--i) templatebool chmax(T &a, const T &b) { if (abool chmin(T &a, const T &b) { if (b dijkstra(vector>>& ab,ll s=0){ ll N=ab.size(); vector dist(N,INF); priority_queue,vector>,greater>> pq; pq.push({0,s}); while(pq.size()){ auto [c,now]=pq.top();pq.pop(); if(dist[now]!=INF) continue; dist[now]=c; for(auto [c2,to]:ab[now]){ pq.push({c+c2,to}); } } return dist; } pair,ll> TreeDiameter(vector>>& ab){ vector dist=dijkstra(ab); ll s=max_element(all(dist))-dist.begin(); dist=dijkstra(ab,s); ll t=max_element(all(dist))-dist.begin(); vector path; ll now=t; while(now!=s){ path.push_back(now); for(auto [c,to]:ab[now]){ if(dist[now]==dist[to]+c){ now=to; break; } } } path.push_back(s); ll diameter=dist[t]; return{path,diameter}; } bool solve(){ ll N;cin>>N; vector ab(N); rep(i,N-1){ ll a,b,c;cin>>a>>b>>c; a--;b--; ab[a].push_back({c,b}); ab[b].push_back({c,a}); } auto [path,r]=TreeDiameter(ab); cout << r << endl; return 0; } int main(){ cin.tie(0); ios::sync_with_stdio(false); ll T=1;//cin>>T; rep(i,T) solve(); }