#include using namespace std; using std::cin; using std::cout; #define rep(i,n) for(int i = 0; i < (int)n; i++) #define FOR(n) for(int i = 0; i < (int)n; i++) #define repi(i,a,b) for(int i = (int)a; i < (int)b; i++) #define all(x) x.begin(),x.end() //#define mp make_pair #define vi vector #define vvi vector #define vvvi vector #define vvvvi vector #define pii pair #define vpii vector> template bool chmax(T &a, const T b) {if(a bool chmin(T &a, const T b) {if(a>b) {a=b; return true;} else {return false;}} using ll = long long; using ld = long double; using ull = unsigned long long; const ll INF = numeric_limits::max() / 2; const ld pi = 3.1415926535897932384626433832795028; const ll mod = 1e9 + 7; int dx[] = {1, 0, -1, 0, -1, -1, 1, 1}; int dy[] = {0, 1, 0, -1, -1, 1, -1, 1}; #define int long long template T_VAL modpow(T_VAL n, T_EXP m, const T_VAL MOD) { // // basically (default), 0^0=1 // // 0^0 = 0にしたいなら以下の行が必要 // if(n == 0) return 0; T_VAL res = 1; while(m > 0) { if(m&1) res = (res*n)%MOD; n = (n*n)%MOD; m >>= 1; } return res; } void solve() { // gcdがbの倍数だと困る int a = 99990, b = 99991; cout << a << " " << b << endl; cout << flush; int k; cin >> k; // x = 9991の時だけやばい? cout << modpow(k, a, b) << endl; int ret; cin >> ret; assert(ret == 1); } int find() { for (int i = 100000; i >= 100; i--) { bool flg = true; repi(j, 1, i) { if (modpow(j, i-1, i) != 1) { flg = false; break; } } cerr << "TEST: " << i << endl; if (flg && modpow(i-1, i, mod) == i) return i; } } signed main() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << find() << endl; // solve(); return 0; }