use itertools::iproduct;
use proconio::{input, marker::Chars};

fn main() {
    input! {
        n: usize,
        mut a: [Chars; n],
    }

    let mut count = 0;
    for (i, j) in iproduct!(0..n, 0..n) {
        if a[i][j] != a[i][n - j - 1] {
            count += 1;
            a[i][n - j - 1] = a[i][j];
        }
    }

    if count % 2 == 0 {
        println!("Yes");
    } else {
        println!("No");
    }
}