#include #include using namespace std; using namespace atcoder; //using mint = modint1000000007; //const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; const int INF = 1e9; const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n) - 1; i >= 0; --i) #define rrep2(i,l,r)for(int i=(r) - 1;i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int op(int a, int b) { return min(a, b); } int e() { return INF; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; string s; cin >> s; int r, m; cin >> r >> m; if (n % 2 != 0) { cout << -1 << endl; return 0; } vectorv(2 * n + 1); rep(i, n) v[i + 1] = v[i] + (s[i] == '(' ? 1 : -1); rep(i, n) v[n + i + 1] = v[n + i] + (s[i] == '(' ? 1 : -1); segtreeseg(v); long long ans = LINF; rrep(l, n + 1) { auto get = seg.prod(l, l + n + 1); int cnt = (v[l] - get + 1) / 2; long long cost = cnt * m; long long x = v[l + n] + 2 * cnt; cost += (x - v[l]) / 2 * m; cost += (n - l) * r; chmin(ans, cost); } cout << ans << endl; return 0; }