#include <iostream>
using ll = long long;
using namespace std;

ll exp_remain(ll b, ll e, ll q) {
	int i;
	ll bp = b % q;
	ll tmp = 1;
	for (i = 0; tmp <= e; i++) {
		tmp *= 2;
	}
	tmp /= 2;
	i--;
	ll ans = 1;
	for (; i >= 0; i--) {
		ans = (ll)ans * (ll)ans;
		ans %= q;
		if ((e >> i) % 2 == 1) {
			ans *= (ll)bp;
		}
		ans %= q;
		tmp /= (ll)2;
	}

	return ans;
}

int main() {
	ll fact[200002];
	fact[0] = 1;
	for (ll i = 1;i <= 200000;i++) {
		fact[i] = (fact[i - 1] * i) % 998244353;
	}
	string N;
	cin >> N;
	ll cnt[10] = { 0 };
	for (int i = 0;i < N.size();i++) {
		cnt[N[i] - 0x30]++;
	}
	ll ans = fact[N.size()];
	for (int i = 0;i <= 9;i++) {
		ans *= exp_remain(fact[cnt[i]], 998244351, 998244353);
		ans %= 998244353;
	}
	if (cnt[0] == 0) {
		cout << ans;
	}
	else {
		ll delta = fact[N.size() - 1];
		cnt[0]--;
		for (int i = 0;i <= 9;i++) {
			delta *= exp_remain(fact[cnt[i]], 998244351, 998244353);
			delta %= 998244353;
		}
		cout << (ans - delta + 998244353) % 998244353;
	}
	return 0;
}