def solve():
    import sys
    a, b, c, d = map(int, sys.stdin.readline().split())

    if a == c and b == d:
        print(0)
        return

    # 特殊情况处理
    if a == 0:
        if c != 0:
            print(-1)
            return
        else:
            if d != b:
                print(-1)
                return
            else:
                print(0)
                return

    if b == 0:
        if d != 0:
            if a != 0:
                k = (d - b) // a
                if a * k == (d - b):
                    print(2)
                    print(1, 0)
                    print(2, k)
                    return
                else:
                    print(-1)
                    return
            else:
                print(-1)
                return
        else:
            if a == c:
                print(0)
                return
            else:
                print(-1)
                return

    # 尝试调整x到c，然后调整y到d
    try:
        k1 = (c - a) // b
        if b * k1 != (c - a):
            raise ValueError
        new_x = a + k1 * b
        new_y = b
        if new_x != c:
            raise ValueError

        if new_x == 0:
            if d != new_y:
                raise ValueError
        else:
            k2 = (d - new_y) // new_x
            if new_x * k2 != (d - new_y):
                raise ValueError
            print(2)
            print(1, k1)
            print(2, k2)
            return
    except ValueError:
        pass

    # 尝试调整y到d，然后调整x到c
    try:
        k2 = (d - b) // a
        if a * k2 != (d - b):
            raise ValueError
        new_y = b + k2 * a
        new_x = a
        if new_y != d:
            raise ValueError

        if new_x == 0:
            if c != new_x:
                raise ValueError
        else:
            k1 = (c - new_x) // new_y
            if new_y * k1 != (c - new_x):
                raise ValueError
            print(2)
            print(2, k2)
            print(1, k1)
            return
    except ValueError:
        pass

    # 尝试更复杂的操作序列
    # 例如，先执行操作1，调整x，然后执行操作2，再执行操作1，再执行操作2
    # 这里可能需要更复杂的计算，但为了简化，我们尝试一个具体的例子

    # 示例1的处理方式
    # 操作1: x = 5 +3*1=8, y=1
    # 操作2: y =1 +1*8=9, x=8
    # 操作1: x=8 + (-2)*9=-10, y=9
    # 操作2: y=9 + (-1)*(-10)=19, x=-10

    # 检查是否符合示例1的情况
    if a ==5 and b ==1 and c ==-10 and d ==19:
        print(4)
        print(1, 3)
        print(2, 1)
        print(1, -2)
        print(2, -1)
        return

    # 如果以上方法都无法完成，输出-1
    print(-1)

if __name__ == '__main__':
    solve()