#include #include using namespace std; using ll = long long int; using u64 = unsigned long long; using pll = pair; // #include // using namespace atcoder; #define REP(i, a, b) for (ll i = (a); i < (b); i++) #define REPrev(i, a, b) for (ll i = (a); i >= (b); i--) #define ALL(coll) (coll).begin(), (coll).end() #define SIZE(v) ((ll)((v).size())) #define REPOUT(i, a, b, exp, sep) REP(i, (a), (b)) cout << (exp) << (i + 1 == (b) ? "" : (sep)); cout << "\n" // @@ !! LIM() int main(/* int argc, char *argv[] */) { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout << setprecision(20); auto solve = [&]() -> void { ll N; cin >> N; // @InpVec(N, A) [2w6s3FHV] auto A = vector(N, ll()); for (int i = 0; i < N; i++) { ll v; cin >> v; A[i] = v; } // @End [2w6s3FHV] vector L(N + 1, 0LL); vector Lx(N + 1, 0LL); vector Ln(N + 1, 0LL); vector R(N + 1, 0LL); REP(i, 0, N) L[i + 1] = L[i] + A[i]; REPrev(i, N - 1, 0) R[i] = R[i + 1] + A[i]; Lx[1] = Ln[1] = L[1]; REP(i, 1, N) Lx[i + 1] = max(Lx[i], L[i + 1]); REP(i, 1, N) Ln[i + 1] = min(Lx[i], L[i + 1]); ll ans = 0; REP(i, 2, N) { ll right = abs(R[i]); ll x1 = Lx[i - 1]; ll x2 = L[i] - x1; ll y1 = Ln[i - 1]; ll y2 = L[i] - y1; ll a = max(abs(x1) + abs(x2), abs(y1) + abs(y2)); ll val = a + right; ans = max(ans, val); } cout << ans << "\n"; }; ll T; cin >> T; REP(t, 0, T) solve(); return 0; }