#include<bits/stdc++.h>
using namespace std;
//#pragma GCC optimize("Ofast")

#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define vtpl(x,y,z) vector<tuple<x,y,z>>
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
//const ll dy[9]={1,0,-1,0,1,1,-1,-1,0};
//const ll dx[9]={0,1,0,-1,1,-1,1,-1,0};
template<class T> inline bool chmin(T& a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template<class T> inline bool chmax(T& a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}


//https://atcoder.jp/contests/abc230/submissions/44985883
vector<tuple<ll,ll,ll>> quotient_floors(ll n){
    //floor(n/i)=xを満たすx,i∈[l,r)をこの順に返す。lの昇順、つまりxの降順なことに注意。
    vector<tuple<ll,ll,ll>> ret;
    for(ll l=1;l<=n;){
        ll x=n/l;
        ll r=n/x+1;
        ret.emplace_back(x,l,r);
        l=r;
    }
    return ret;
}


struct osak{
    vector<long long> lpf;// least prime factor
    vector<long long> prime;// prime table
    osak(long long n){//linear_sieve
        lpf=vector<long long>(n+1,-1);
        for (int d = 2; d <= n; ++d) {
          if(lpf[d]==-1){
            lpf[d]=d;prime.emplace_back(d);
          }
          for(auto p:prime){
            if(p*d>n||p>lpf[d])break;
            lpf[p*d]=p;
          }
        }
    }
    map<long long,long long> factor(int n) {
        map<long long,long long> factor;
        while (n > 1) {
            factor[lpf[n]]++;
            n /= lpf[n];
        }
        return factor;
    }

    vector<long long> divisor(int N){//O(div.size())
        map<long long,long long> facs=factor(N);
        vector<long long> ret={1};
        for(auto p:facs){
            ll range=ret.size();
            ll now=1;
            for(int i=0;i<p.se;i++){
                now*=p.fi;
                for(int j=0;j<range;j++){
                    ret.emplace_back(ret[j]*now);
                }
            }
        }
        sort(ret.begin(),ret.end());
        return ret;
    }
};


ll modpow(ll a,ll n, ll mod) {
  a%=mod;if(a==0)return 0;
  ll res = 1;
  while (n > 0) {
      if (n & 1) res = res * a % mod;
      a = a * a % mod;
      n >>= 1;
  }
  return res;
}


int main(){
    ll n,p;cin >> n >> p;
    //for(auto [p,q,r]:quotient_floors(99))cout << p <<" " << q <<" " << r << endl;
    vl ans(n+1);
    //osak os(300010);
    vvl divs(300010);
    for(ll i=1;i<=n;i++){
        for(ll j=i;j<=n;j+=i){
            divs[j].emplace_back(i);
        }
    }
    vvl dp(n+1);
    for(ll i=1;i<=n;i++){
        rep(_,n/i+5)dp[i].emplace_back(0);
    }
    for(ll i=3;i<=n;i++){
        ll sum=1;
        ll cof=1;
        ll inv=modpow(i,p-2,p);
        for(auto x:divs[i]){
            dp[x][i/x+1]=dp[x][i/x];
            cof=(cof-inv+p)%p;
        }
        for(auto [x,y,z]:quotient_floors(i)){
            sum+=(dp[x][z]-dp[x][y]+p)%p*inv;
            sum%=p;
        }
        ans[i]=sum*modpow(cof,p-2,p)%p;
        //cout << sum <<" " << cof << endl;
        for(auto x:divs[i]){
            dp[x][i/x+1]=(dp[x][i/x+1]+ans[i])%p;
        }
    }
    cout << ans.back() << endl;

}