#include using namespace std; using ll = long long; template void print(_ForwardIterator first, _ForwardIterator last) { bool f = true; for (auto it = first; it != last; ++it) { if (!f) { cout << " "; } cout << *it; f = false; } cout << endl; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); int N, K; cin >> N >> K; ll X, Y; cin >> X >> Y; // 解説の通りの場合分け if (Y == 0) { cout << "No" << endl; return 0; } else if (X == 0 && K >= 2) { if (N >= K + 3) { vector A(N); if (K % 2 == 0) { A[0] = 0; A[1] = 1; for (int i = 2; i < N - 1; i++) { A[i] = 3; } A[N - 1] = Y; } else if (K % 3 == 0) { A[0] = 0; A[1] = 3; vector cycle = {1, 3, 2}; for (int i = 2; i < N - 1; i++) { A[i] = cycle[(i - 2) % 3]; } A[N - 1] = Y; } else if (K % 3 == 1) { A[0] = 0; A[1] = 2; A[2] = 2; for (int i= 3; i < N - 1; i++) { int pos = (i - 3) % K; if (pos < 2) { A[i] = 3; } else if (pos >= K - 2) { A[i] = 2; } else { A[i] = ((pos - 2) % 3) + 1; } } A[N - 1] = Y; } else if (K % 3 == 2) { A[0] = 0; A[1] = 2; for (int i = 2; i < N - 1; i++) { int pos = (i - 2) % K; if (pos < K - 2) { A[i] = pos % 3 + 1; } else { A[i] = 3; } } A[N - 1] = Y; } cout << "Yes" << endl; print(A.begin(), A.end()); return 0; } else if (N == K + 1) { vector A(N); A[N - 1] = Y; cout << "Yes" << endl; print(A.begin(), A.end()); return 0; } else if (N == K + 2) { if (Y == 1) { cout << "No" << endl; return 0; } else { vector A(N); A[N - 2] = 1; A[N - 1] = Y; cout << "Yes" << endl; print(A.begin(), A.end()); return 0; } } } else if (K == 1) { vector A(N); if (Y - X >= N - 1) { for (int i = 0; i < N; i++) { A[i] = X + i; } A[N - 1] = Y; cout << "Yes" << endl; print(A.begin(), A.end()); return 0; } else { cout << "No" << endl; return 0; } } else { vector A(N); vector B(K); if (K % 2 == 0) { for (int i = 0; i < K; i++) { B[i] = X; } } else { for (int i = 0; i < K - 3; i++) { B[i] = X; } if (__popcount(X) == 1) { int p = 0; while ((X & (1L << p)) != 0) p++; B[K - 3] = X; B[K - 2] = X | (1L << p); B[K - 1] = 1L << p; } else { int p = 0; while ((X & (1L << p)) == 0) p++; B[K - 3] = X; B[K - 2] = X ^ (1 << p); B[K - 1] = 1L << p; } } for (int i = 0; i < N; i++) { A[i] = B[i % K]; } A[N - 1] = Y; cout << "Yes" << endl; print(A.begin(), A.end()); return 0; } }