#include using namespace std; using ll = long long; static const ll INF = (ll)4e18; struct Edge { int to; ll cap; int rev; }; struct Dinic { int N; vector> G; vector level, ptr; Dinic(int n) : N(n), G(n), level(n), ptr(n) {} void add_edge(int u, int v, ll c) { G[u].push_back({v, c, (int)G[v].size()}); G[v].push_back({u, 0, (int)G[u].size() - 1}); } bool bfs(int s, int t) { fill(level.begin(), level.end(), -1); queue q; level[s] = 0; q.push(s); while (!q.empty()) { int u = q.front(); q.pop(); for (auto &e : G[u]) { if (level[e.to] < 0 && e.cap > 0) { level[e.to] = level[u] + 1; q.push(e.to); } } } return level[t] >= 0; } ll dfs(int u, int t, ll f) { if (u == t) return f; for (int &i = ptr[u]; i < (int)G[u].size(); i++) { Edge &e = G[u][i]; if (e.cap > 0 && level[e.to] == level[u] + 1) { ll pushed = dfs(e.to, t, min(f, e.cap)); if (pushed > 0) { e.cap -= pushed; G[e.to][e.rev].cap += pushed; return pushed; } } } return 0; } ll max_flow(int s, int t) { ll flow = 0; while (bfs(s, t)) { fill(ptr.begin(), ptr.end(), 0); while (true) { ll pushed = dfs(s, t, INF); if (pushed == 0) break; flow += pushed; } } return flow; } }; int main() { int N; cin >> N; vector P(N); for (int i = 0; i < N; i++) cin >> P[i]; int M; cin >> M; vector> deps(M); for (int i = 0; i < M; i++) { cin >> deps[i].first >> deps[i].second; --deps[i].first; --deps[i].second; } int K; cin >> K; vector> syn(K); for (int j = 0; j < K; j++) { int A, B; ll S; cin >> A >> B >> S; --A; --B; syn[j] = {A, B, S}; } int S = N + K, T = N + K + 1; Dinic mf(N + K + 2); ll totalPos = 0; for (int i = 0; i < N; i++) { if (P[i] >= 0) { mf.add_edge(S, i, P[i]); totalPos += P[i]; } else { mf.add_edge(i, T, -P[i]); } } for (auto &d : deps) { int u, v; tie(u, v) = d; mf.add_edge(v, u, INF); } for (int j = 0; j < K; j++) { int node = N + j; ll S_j = get<2>(syn[j]); mf.add_edge(S, node, S_j); totalPos += S_j; // 取るなら両都市を取る => node->A, node->B に無限容量 int A = get<0>(syn[j]), B = get<1>(syn[j]); mf.add_edge(node, A, INF); mf.add_edge(node, B, INF); } ll mincut = mf.max_flow(S, T); ll answer = totalPos - mincut; cout << answer << "\n"; return 0; }