#include using namespace std; typedef long long ll; typedef long double ld; typedef pair Pii; typedef pair Pil; typedef pair Pll; typedef pair Pli; typedef vector> Mat; #define fi first #define se second const ll MOD = 1e9 + 7; const ll MOD2 = 998244353; const ll MOD3 = 1812447359; const ll INF = 1ll << 62; const double PI = 2 * asin(1); void yes() { printf("yes\n"); } void no() { printf("no\n"); } void Yes() { printf("Yes\n"); } void No() { printf("No\n"); } void YES() { printf("YES\n"); } void NO() { printf("NO\n"); } int n, m, a[int(2e5 + 5)], b[int(2e5 + 5)]; vector graph[int(4e5 + 5)]; int ans[int(4e5 + 5)]; void solve(int start, int cnt) { queue que; que.push(start); ans[start] = cnt; while (!que.empty()) { int q = que.front(); que.pop(); for (int next : graph[q]) { if (ans[next] == 0) { ans[next] = cnt; que.push(next); } } } return; } int main() { cin >> n >> m; for (int i = 1; i <= m; i++) { cin >> a[i] >> b[i]; graph[a[i]].push_back(b[i] + n); graph[a[i] + n].push_back(b[i]); graph[b[i]].push_back(a[i] + n); graph[b[i] + n].push_back(a[i]); } int cnt = 1; for (int i = 1; i <= 2 * n; i++) { if (ans[i] == 0) { solve(i, cnt); cnt++; } } for (int i = 1; i <= n; i++) { if (ans[i] != ans[i + n]) { No(); return 0; } } Yes(); return 0; }