#include using namespace std; typedef long long ll; typedef long double ld; typedef pair Pii; typedef pair Pil; typedef pair Pll; typedef pair Pli; typedef vector> Mat; #define fi first #define se second const ll MOD = 1e9 + 7; const ll MOD2 = 998244353; const ll MOD3 = 1812447359; const ll INF = 1ll << 62; const double PI = 2 * asin(1); void yes() { printf("yes\n"); } void no() { printf("no\n"); } void Yes() { printf("Yes\n"); } void No() { printf("No\n"); } void YES() { printf("YES\n"); } void NO() { printf("NO\n"); } int k, n; bool is_prime[int(2e5 + 5)], visited_prime[int(2e5 + 5)]; vector primes; int my_hash[int(2e5 + 5)]; bool visited[int(2e5 + 5)]; void prepare() { for (int i = 2; i <= n; i++) { if (visited_prime[i]) { continue; } visited_prime[i] = true; is_prime[i] = true; for (int j = i; j <= n; j += i) { visited_prime[j] = true; } } for (int i = k; i <= n; i++) { if (is_prime[i]) { primes.push_back(i); } } return; } int calc_hash(int num) { if (visited[num]) { return my_hash[num]; } visited[num] = true; if (num <= 9) { return my_hash[num] = num; } int ans = 0, rest = num; while (rest > 0) { ans += rest % 10; rest /= 10; } return my_hash[num] = calc_hash(ans); } int main() { cin >> k; cin >> n; prepare(); int ans_c = 0, ans_p = 0; for (int i = 0; i < primes.size(); i++) { int cnt = 0; bool now_visited[10] = {}; for (int j = 0; i + j < primes.size(); j++) { int h = calc_hash(primes[i + j]); if (now_visited[h]) { break; } else { now_visited[h] = true; cnt++; } } if (ans_c <= cnt) { ans_c = cnt; ans_p = primes[i]; } } cout << ans_p << endl; return 0; }