#include using namespace std; //#pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,1,0,-1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } ll nand(ll a,ll b){ ll z=a&b; return z^(15); } void solve(ll q,ll k){ vl v={12,10}; bool ok=false; vpl memo; auto dfs=[&](auto &self,vl v,vpl ope)->void { if(v.size()==q){ vl dp(4); rep(i,q+2){ rep(j,4)dp[j]+=(v[i]>>j)&1; } if(*max_element(all(dp))<=k){ ok=true;memo=ope; } //if(v.back()==0){rep(i,7)cout << v[i] <<" ";cout << endl;} return; } ll n=v.size(); rep(i,n){ rep(j,i){ v.emplace_back(nand(v[j],v[i])); ope.push_back({j,i}); self(self,v,ope); v.pop_back(); ope.pop_back(); } } }; vpl op; dfs(dfs,v,op); if(ok){ cout << "Yes" << endl; for(auto p:memo)cout << p.first+1 <<" " << p.second+1 << endl; } else { cout << "No" << endl; } } int main(){ ll q,k;cin >> q >> k; if(q<=8){ solve(q,k); return 0; } vpl ope={{1,2},{1,2},{3,4},{4,5},{4,5}}; while(ope.size()>j)&1; } if(*max_element(all(dp))<=k){ cout << "Yes" << endl; rep(_,q)cout << ope[_].first <<" " << ope[_].second << endl; } else { cout << "No" << endl; } }