#include using namespace std; typedef long long ll; typedef long double ld; typedef pair Pii; typedef pair Pil; typedef pair Pll; typedef pair Pli; typedef vector> Mat; #define fi first #define se second const ll MOD = 1e9 + 7; const ll MOD2 = 998244353; const ll MOD3 = 1812447359; const ll INF = 1ll << 62; const double PI = 2 * asin(1); void yes() { printf("yes\n"); } void no() { printf("no\n"); } void Yes() { printf("Yes\n"); } void No() { printf("No\n"); } void YES() { printf("YES\n"); } void NO() { printf("NO\n"); } int n, k, q; ll a[int(1e5 + 5)], x[int(1e5 + 5)]; ll sum[int(1e5 + 5)]; vector vals; int solve(ll num) { if (num < vals[0]) { return 0; } int ok = 0, ng = vals.size(); while (ng - ok > 1) { int mid = (ok + ng) / 2; if (vals[mid] <= num) { ok = mid; } else { ng = mid; } } return ok + 1; } int main() { cin >> n >> k; for (int i = 1; i <= n; i++) { cin >> a[i]; sum[i] = sum[i - 1] + a[i]; } cin >> q; for (int i = 1; i <= q; i++) { cin >> x[i]; } for (int i = 1; i + k - 1 <= n; i++) { vals.push_back(sum[i + k - 1] - sum[i - 1]); } sort(vals.begin(), vals.end()); for (int i = 1; i <= q; i++) { cout << solve(x[i]) << endl; } return 0; }