#include #include //小数点出力用 //cout << fixed << setprecision(10) << ans; #include #include #include #include #include #include #include #include using ll = long long; using namespace std; #define modPHash (ll)((1LL<<61)-1) #define modP (ll)998244353 bool chkrng0idx(int pos, int sup) { return (0 <= pos && pos < sup); } int clk4(int num) { return (num - 2) * (num % 2); } void yn(bool tf) { cout << (tf ? "Yes\n" : "No\n"); } vector> mul(vector>& A, vector>& B, int size) { vector>res; for (int i = 0; i < size; i++) { vectorrow; for (int j = 0; j < size; j++) { ll tmp = 0; for (int k = 0; k < size; k++) { tmp += A[i][k] * B[k][j]; } row.push_back(tmp); } res.push_back(row); } return res; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); vectorI(2); vector>A(2, I); for (int i = 0;i < 2;i++) { for (int j = 0;j < 2;j++) { cin >> A[i][j]; } } ll S, T, N, K; cin >> S >> T >> N >> K; for (int i = 0;i < 2;i++) { for (int j = 0;j < 2;j++) { A[i][j] %= K; A[i][j] += K; A[i][j] %= K; } } S %= K; S += K; S %= K; T %= K; T += K; T %= K; vector> EX[64]; EX[0] = A; for (int k = 1;k < 64;k++) { EX[k] = mul(EX[k - 1], EX[k - 1], 2); for (int i = 0;i < 2;i++) { for (int j = 0;j < 2;j++) { EX[k][i][j] %= K; } } } for (int k = 0;k < 64;k++) { if ((N >> k) & 1) { ll SS = (S * EX[k][0][0] + T * EX[k][0][1]) % K; ll TT = (S * EX[k][1][0] + T * EX[k][1][1]) % K; S = SS; T = TT; } } cout << S << " " << T; return 0; }