#include using namespace std; typedef long long ll; typedef long double ld; typedef pair Pii; typedef pair Pil; typedef pair Pll; typedef pair Pli; typedef vector> Mat; #define fi first #define se second const ll MOD = 1e9 + 7; const ll MOD2 = 998244353; const ll MOD3 = 1812447359; const ll INF = 1ll << 62; const double PI = 2 * asin(1); void yes() { printf("yes\n"); } void no() { printf("no\n"); } void Yes() { printf("Yes\n"); } void No() { printf("No\n"); } void YES() { printf("YES\n"); } void NO() { printf("NO\n"); } ll mod; int n, q; Mat a = {{0, 0}, {0, 0}}, ans[int(1e5 + 5)]; Mat my_calc(Mat a, Mat b, ll mod) { Mat ans = {{0, 0}, {0, 0}}; for (int i = 0; i < 2; i++) { for (int j = 0; j < 2; j++) { for (int k = 0; k < 2; k++) { ans[i][j] += a[i][k] * b[k][j]; ans[i][j] %= mod; if (ans[i][j] < 0) { ans[i][j] += mod; } } } } return ans; } struct SegmentTree { private: int n; vector node; public: SegmentTree(int sz) { n = 1; while (n < sz) { n *= 2; } node.resize(2 * n - 1, {{0, 0}, {0, 0}}); } void insert(int idx, Mat m, ll mod) { idx += n - 1; node[idx] = m; while (idx > 0) { idx = (idx - 1) / 2; node[idx] = my_calc(node[2 * idx + 1], node[2 * idx + 2], mod); } return; } Mat solve(int a, int b, ll mod, int idx = 0, int l = 0, int r = -1) { if (r == -1) { r = n; } if (b <= l || r <= a) { return {{1, 0}, {0, 1}}; } if (a <= l && r <= b) { return node[idx]; } return my_calc(solve(a, b, mod, 2 * idx + 1, l, (l + r) / 2), solve(a, b, mod, 2 * idx + 2, (l + r) / 2, r), mod); } }; int main() { cin >> mod >> n; SegmentTree tree(n + 5); for (int i = 1; i <= n; i++) { for (int j = 0; j < 2; j++) { for (int k = 0; k < 2; k++) { cin >> a[j][k]; } } tree.insert(i, a, mod); } cin >> q; for (int i = 1; i <= q; i++) { int idx, l, r; cin >> idx >> l >> r; for (int j = 0; j < 2; j++) { for (int k = 0; k < 2; k++) { cin >> a[j][k]; } } tree.insert(idx, a, mod); ans[i] = tree.solve(l, r + 1, mod); } for (int i = 1; i <= q; i++) { for (int j = 0; j < 2; j++) { cout << ans[i][j][0] << " " << ans[i][j][1] << endl; } } return 0; }