#include using namespace std; typedef signed long long ll; #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define FORR2(x,y,arr) for(auto& [x,y]:arr) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) template bool chmax(T &a, const T &b) { if(a bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;} //------------------------------------------------------- int N; ll K; int P[202020]; vector ret[5][31]; ll ma[202020],mi[202020]; void solve() { int i,j,k,l,r,x,y; string s; cin>>N>>K; for(i=1;i<=200000;i++) { ma[i]=1LL*i*(i+1)*(2*i+1)/6; mi[i]=1LL*i*(i+1)*(i+2)/6; } if(Kma[N]) { cout<<"No"< V; FOR(j,i) V.push_back(j+1); do { int sum=0; FOR(j,i) { sum+=(j+1)*V[j]; } ret[i][sum]=V; } while(next_permutation(ALL(V))); } if(N<=4) { if(ret[N][K].empty()) { cout<<"No"<=5;i--) { ll a=1LL*i*(i+1)/2; if(K-a>=mi[i-1]&&K-a<=ma[i-1]) { K-=a; P[N-i]=R--; continue; } a=1LL*i*i; assert(K-a>=mi[i-1]&&K-a<=ma[i-1]); K-=a; P[N-i]=L++; } FOR(i,4) P[N-4+i]=ret[4][K][i]+L-1; cout<<"Yes"<