#include using namespace std; using ll=long long; const ll ILL=2167167167167167167; const int INF=2100000000; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template int LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template int UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,T b){if(b bool chmax(T &a,T b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} bool yneos(bool a,bool upp=false){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} template T square(T a){return a * a;} #include using mint = atcoder::modint998244353; bool f(ll x){ if (x < 10) return true; ll sum = 0; ll tmp = INF; while (x){ ll r = x % 10; x /= 10; sum += r; if (tmp < r) return false; tmp = r; } return f(sum); } ll upd(ll tmp){ auto X = to_string(tmp); rep(i, 1, X.size()){ if (chmax(X[i], X[i - 1])){ rep(j, i, X.size()) X[j] = X[i]; break; } } tmp = stol(X); return tmp; } void solve(); // POP'N ROLL MUSIC / TOMOO int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t = 1; cin >> t; rep(i, 0, t) solve(); } void solve(){ ll N; cin >> N; ll tmp = N; do{ tmp++; tmp = upd(tmp); // cout << X << endl; }while(!f(tmp)); // digi を求める ll D = max((tmp + 8) / 9, N + 1); // A + B + C * 9 = tmp // A + 1 + C = D ll C = (tmp - D) / 8; if (C == D){ cout << (((mint)(10)).pow(D) - 1).val() << "\n"; return; } ll B = (tmp - C * 8) - D + 1; ll A = D - C - 1; // cout << tmp << " " << A << " " << B << " " << C << endl; mint ans = (((mint)(10)).pow(C) * (B + 1) - 1); ans += (((mint)(10)).pow(D) - (mint(10)).pow(C + 1)) / 9; cout << ans.val() << "\n"; }